Question

Among the following compounds, the one that is polar and has central atom with $s{p}^3$ hybridisation is:

• A. $H_{2}C{O}_3$
• B. $Si{F}_4$
• C. $B{F}_3$
• D. $HCl{O}_2$

Answer 1

The correct option is D $HCl{O}_2$

Option (a)
Here, Central atom (C) is having 3 $\sigma$ bonds and zero lone pair. So steric number is $3+0=3$. So Hybridisation is $s{p}^2$. Also it is having trigonal planar structure.

Option(b)
Here, Central atom ($Si$) is having 4 $\sigma$ bonds and zero lone pair. So steric number is $4+0=4$. So Hybridisation is $s{p}^3$. It has regular tetrahedral geometry and is non-polar.

In Option (c) and (d)

Here, Central atom (B) is having 3 $\sigma$ bonds and zero lone pair. So steric number is $3+0=3$. So Hybridisation is $s{p}^2$. Also it is having symmetrical trigonal planar structure so it is non-polar.


In $HCl{O}_2$ Central atom (C) is having 2 $\sigma$ bonds and two lone pair. So steric number is $2+2=4$. So Hybridisation is $s{p}^3$. Since it is having unsymmetrical angular structure so it is polar.