Among the following compounds, the strongest acid is:

C l

C H_{2}

C O O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H

C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3}

C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3}

C H_{2}

C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C l$ - $C H_{2}$ - $C O O H$
The halogenated fatty acids are much stronger acids than their parent fatty acids because of $- I$ effect i.e. electron-withdrawing inductive effect.
$- C l$ is the second-highest electronegative element of the periodic table after $F$ .
$- C_{2} H_{5}$ produces $+ I$ effect which decreases the acidic strength by increasing the negative charge on the carboxylate ion.

Therefore, option $A$ is correct.

Suggest Corrections

Similar questions

C H_{3} - C O O H

C H_{2} = C H - C O O H

C_{6} H_{5} - C O O H

C_{6} H_{5} - C H_{2} - C O O H

C H_{3} - C H_{2} - C O O H

C H_{3} - C H | O H - C O O H

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

C H_{3} - C H_{2} - C O O H + B r_{2} P B r_{3} - -- \to C H_{3} - C | B r H - C O O H

H_{2} O, C H_{3} N H_{2} - -------- \to

C H_{3} - C | N H_{2} H - C O O H

C H_{3} C O C H_{3}, C_{6} H_{5} C O C H_{3}, C H_{3} C H O

C I - C H_{2} - C O O H, F - C H_{2} - C O O H, C H_{3} - C O O H

Join BYJU'S Learning Program