Question

Among the following coordination compounds, the one giving a white precipitate with $BaC{l}_2$ solution is:

• A. $\left[Cr\right(H_{2}O{)}_{5}Br]S{O}_4$
• B. $\left[Cr\right(H_{2}O{)}_{5}SCN]$
• C. $\left[Co\right(N{H}_3{)}_{5}S{O}_4]Br$
• D. $\left[Pt\right(N{H}_3{)}_6]C{l}_4$

Answer 1

The correct option is A $\left[Cr\right(H_{2}O{)}_{5}Br]S{O}_4$

Among the following coordination compounds, the one giving a white precipitate with $BaC{l}_2$ solution is $\left[Cr\right(H_{2}O{)}_{5}Br]S{O}_4$.

It dissociates in aqueous solution to give sulphate ions. Sulphate ions react with barium chloride to form a white precipitate of barium sulphate.

$\left[Cr\right(H_{2}O{)}_{5}Br]S{O}_4\to [Cr(H_{2}O{)}_{5}Br{]}^{2+}+S{O}_4^{2-}$

$S{O}_4^{2-}+BaC{l}_2\to BaS{O}_4\downarrow +2C{l}^{-}$

Hence, option $A$ is correct.