Among the following electronic configurations, the one which represents the element with lowest ionisation potential is:

1 s^{2} 2 s^{2} 2 p^{5}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

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1 s^{2} 2 s^{2} 2 p^{2}

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Solution

The correct option is C $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
Among the given electronic configurations, the one which represents the element with lowest ionisation potential is $1 s^{1} 2 s^{2} 2 p^{6} 3 s^{1}$ . It is an alkali metal with one valence electron which can be easily lost to attain stable electronic configuration of nearest noble gas with completed octet.
Note:
The ionisation potential of the s block elements is lower than that of p block elements. Of the given options, the electronic configuration in option C belongs to s block whereas the rest of the electronic configurations belongs to p block.

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Similar questions

A, B, C

D

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2}

1 s^{2} 2 s^{2} 2 p^{2}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

1 s^{2} 2 s^{2} 2 p^{3}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

A = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

B = 1 s^{2} 2 s^{2} 2 p^{5}

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