Question

Among the following factor, the most important in making fluorine the strongest oxidizing agent is:

• A. electron affinity
• B. ionization energy
• C. hydration enthalpy
• D. bord dissociation enthalpy

Answer 1

Answer: (C)

hydration enthalpy

Oxidizing power of an element depends on the ability to accept electrons on the hydration energy.Hydration enthalpy is the heat released at constant temperature and pressure towards the water. It depends on the charge to radius ratio F due to its small size has high hydration enthalpy. $F$ has greater positive electrode potential so has greater oxidizing power.