The correct option is A CO,NO+,CN−,C2−2
In option A, each species contains 14 electrons
CO= 6(carbon) + 8(oxygen) =14
NO+= 7(nitrogen) + 8(oxygen) - 1(the positive charge) =14
CN−= 6(carbon) + 7(nitrogen) + 1(the negative charge) =14
C−22= 6(carbon) + 6(carbon) + 2(-2 negative charge) =14
So, A is the correct answer.