Question

Among the following hydroxides, the one which has the lowest value of $K_{sp}$ at ordinary temperature (about ${25}^{o}C$) is:

• A. $Mg(OH{)}_2$
• B. $Ca(OH{)}_2$
• C. $Ba(OH{)}_2$
• D. $Be(OH{)}_2$

Answer 1

The correct option is D $Be(OH{)}_2$

As we move down a group in periodic table, solubility of hydroxides increases. So, $Be(OH{)}_2$ will have lowest solubility and $K_{sp}$ value.