Question

Among the following ions, the $p\pi -d\pi$ overlapping could be present in

• A. $P{O}_4{}^{3-}$
• B. $N{O}_2^{-}$
• C. $N{O}_3^{-}$
• D. $C{O}_3^{2-}$

Answer 1

The correct option is A

$P{O}_4{}^{3-}$

In $P{O}_4^{-3}$, $P$ is $s{p}^3$ hybridise, it forms four $P-O$ $\sigma$ bonds by overlap of $sp=3-$ orbitals of $P$ with $p-$orbits of $O$. the bond is, however, formed byoverlap of $p-$orbitals of $O$ and $d-$orbit of $P,N$ and $C,$ on the other hand, can't form $p\pi -d\pi$ bond, since they do not have $d-$orbits