Among the following molecules, the correct order of $C - C$ bond length is:

C_{2} H_{6} > C_{2} H_{4} > C_{6} H_{6} > C_{2} H_{2}

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C_{2} H_{6} > C_{6} H_{6} > C_{2} H_{4} > C_{2} H_{2} (C_{6} H_{6}

is benzene)

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C_{2} H_{4} > C_{2} H_{6} > C_{2} H_{2} > C_{6} H_{6}

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C_{2} H_{6} > C_{2} H_{4} > C_{2} H_{2} > C_{6} H_{6}

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Solution

The correct option is C $C_{2} H_{6} > C_{6} H_{6} > C_{2} H_{4} > C_{2} H_{2} (C_{6} H_{6}$ is benzene)
Ethane contains carbon-carbon single bond.
Benzene is aromatic in nature. It has resonance. All the carbon-carbon bonds in benzene have partial double bond character.
Ethylene contains carbon-carbon double bond.
Acetylene contains carbon-carbon triple bond.
The order of bond length is, single bond>partial double bond> double bond > triple bond.
Hence, the correct order of carbon-carbon bond length is $C_{2} H_{6} > C_{6} H_{6} > C_{2} H_{4} > C_{2} H_{2}$ .

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Similar questions

C_{2} H_{4}

C_{2} H_{2}

C_{6} H_{6}

C_{2} H_{6}

C - H

I \to C_{2} H_{2},

I I \to C_{2} H_{4},

I I I \to C_{2} H_{6}

List - A	List - B
(Molecule)	(Pure and hybrid orbitals involved)
A) $C_{2} H_{6}$	1) 12, 18
B) $C_{2} H_{4}$	2) 6, 4
C) $C_{2} H_{2}$	3) 6, 6
D) $C_{6} H_{6}$	4) 6, 8

C_{2} H_{6}, C_{2} H_{4}

C_{2} H_{2}

C H

C_{2} H_{6}, C_{2} H_{4}

C_{2} H_{2}

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