Question

Among the following series of transition metal ions, the one where all metal ions have $3d^2$ electronic configuration is :

• A. $T{i}^{2+},V^{3+},C{r}^{4+},M{n}^{5+}$
• B. $T{i}^{2+},V^{2+},C{r}^{3+},M{n}^{4+}$
• C. $T{i}^{+},V^{4+},C{r}^{6+},M{n}^{7+}$
• D. $T{i}^{4+},V^{3+},C{r}^{2+},M{n}^{3+}$

Answer 1

The correct option is A $T{i}^{2+},V^{3+},C{r}^{4+},M{n}^{5+}$

The electronic configurations of neutral atoms are as given.

$Ti:\left[Ar\right]3d^{2}4s^{2}V:\left[Ar\right]3d^{3}4s^{2}Cr:\left[Ar\right]3d^{5}4s^{1}Mn:\left[Ar\right]3d^{5}4s^2$

Among the given series of transition metal ions, the one where all metal ions have $3d^2$ electronic configuration is $T{i}^{2+},V^{3+},C{r}^{4+},M{n}^{5+}$.

Hence, option $A$ is correct.