The correct option is B [BF3,NO−3]
Isoelectronic species have same number of electrons and Isostructural species have same hybridisation at the central atom.
Steric Number (x) = 12(M + V − C+A).
where, M = number of monovalent surrounding atoms
V = number of valence electrons on the central atom
C = charge (with sign)
A=charge on anion
NF3
number of electron=7+9×3=34
Steric Number (x)=12(3+5−0+0).
Steric Number (x)=4.
Hybridisation =sp3
NO−3
number of electron=7+8×3+1=32
Steric Number (x)=12(0+5−0+1).
Steric Number (x)=3.
Hybridisation =sp2
BF3
number of electron=5+9×3=32
Steric Number (x)=12(3+3−0+0).
Steric Number (x)=3.
Hybridisation =sp2
[BF3,NO−3] are isoelectronic and isostructural pairs.