The correct option is
B VOSO4In K2Cr2O7, the Cr is in +6 oxidation state.
Electronic configuration of Cr+6=3d0
In (NH4)2[TiCl6], the Ti is in +4 oxidation state.
Electronic configuration of Ti+4=3d0
In VOSO4, V is in +4 oxidation state.
Electronic configuration of V+4=3d1
It contains 1 unpaired electron.
K3[Cu(CN)4]→Cu+:3d10
VOSO4, due to the presence of one unpaired electron, is paramagnetic and coloured.
Hence, option C is the answer.