Among the following, the diamagnetic compound is/ are:

N a_{2} O_{2}

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O_{3}

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N_{2} O

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K O_{2}

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Solution

The correct options are
B $N a_{2} O_{2}$
C $N_{2} O$
D $O_{3}$
If the number of electrons is even, then the molecule is usually diamagnetic - If all the electrons are paired.
A) $N a_{2} O_{2}$ ( $11 \times 2 + 8 \times 2 = 38$ even number of electrons), so diamagnetic.
B) $O_{3}$ ( $3 \times 8 = 24$ even number of electrons), so diamagnetic.
C) $N_{2} O$ ( $2 \times 7 + 8 = 22$ even number of electrons), so diamagnetic.
D) $K O_{2}$ ( $19 + 2 \times 8 = 35$ odd number of electrons), so paramagnetic.
Hence options $A, B$ and $C$ are correct.

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The correct statement(s) about $O_{3}$ is(are):

$N a_{2} O_{2}$ is

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