Among the following the most reactive towards alcoholic KOH is :

CH₂ = CHBr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

CH₃COCH₂CH₂Br

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

CH₃CH₂Br

No worries! We‘ve got your back. Try BYJU‘S free classes today!

CH₃CH₂Cl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
CH₃COCH₂CH₂Br

(with drawing group makes more fast elimination of proton)

Suggest Corrections

Similar questions

K O H

H - X

C H_{2} = C H - O H

C H_{2} = C H - C H_{2} O H

C H_{3} - C H_{2} - O H

C H_{3} - C H | O H - C H_{3}

Join BYJU'S Learning Program