Question

Among the following, the number of halide$\left(s\right)$ which is/are inert to hydrolysis
$\left(A\right)B{F}_3$
$\left(B\right)SiC{l}_4$
$\left(C\right)PC{I}_5$
$\left(D\right)S{F}_6$


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Answer 1

$B{F}_3-$ shows Partial hydrolysis
$4B{F}_3+3H_{2}O\to H_{3}B{O}_3+3HB{F}_4$
$SiC{l}_4-$ Undergoes hydrolysis readily.
$SiC{l}_4+4H_{2}O\to Si(OH{)}_4+4HCl$
$PC{l}_5-$ Undergoes hydrolysis by addition-elimination mechanism.
$PC{l}_5+H_{2}O\to POC{l}_3+2HCl$
$S{F}_6-$ Inert towards hydrolysis.
SF6 is an inert, gas. Its inertness is due to the presence of sterically protected sulphur atom by six F atoms which does not permit the reactions like hydrolysis to take place.
So correct answer is 1