Among the following, the one that gives positive Iodoform test upon reaction with I2/NaOH
Compound A (C5H10O) forms a phenyl hydrazone and gives a negative Tollen's test and negative iodoform test. On reducing A with Zn - Hg / HCl, n - pentane is formed. The compound A is
2 moles of iso-pentylene on reaction with compound A gives compound B, which on treatment with 1-phenyl-2-butyne followed by oxidation with H2O2 and NaOH results in the compound C. A is in turn generated by treating BCl3, with LiAlH4. The compound C gives: