Among the following, the orbitals that have the lowest energy is
6s
The energy of any orbital is given by the (n+l) Rule.
Subshell | Azimuthal quantum number |
s | 0 |
p | 1 |
d | 2 |
f | 3 |
For 5f: n=5, l=3
n+l=5+3=8
For 4f: n=4, l=3
n+l=4+3=7
For 6s: n=6, l=0
n+l=6+0=6
For 6p: n=6, l=1
n+l=6+1=7
Conclusion statement: Option (c) is the correct answer.