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Question

Among the following, the orbitals that have the lowest energy is


A

5f

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B

4f

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C

6s

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D

6p

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Solution

The correct option is C

6s


The energy of any orbital is given by the (n+l) Rule.

SubshellAzimuthal quantum number
s0
p1
d2
f3

For 5f: n=5, l=3

n+l=5+3=8

For 4f: n=4, l=3

n+l=4+3=7

For 6s: n=6, l=0

n+l=6+0=6

For 6p: n=6, l=1

n+l=6+1=7

Conclusion statement: Option (c) is the correct answer.


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