The correct option is C [1,0,2], [0,5,0]
The two vectors X1 & X2 are said to be orthogonal if X1.X2 = 0
Let X1 = [102]T and X2 = [050]T
So, X1,X2 = ⎡⎢⎣102⎤⎥⎦.⎡⎢⎣050⎤⎥⎦ = 1x0+0x5+2x0 = 0
Methos II:
For orthogonal vectors : →a.→b = 0
i.e. if →a = x1i+y1j+z1k
& →b = x2i+y2j+z2k
Then: x1x2+y1y2+z1z2 = 0
Option 'c' satisfies the condition.