Among the following , the paramagnetic compound is :

N a_{2} O_{2}

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O_{3}

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N_{2} O

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K O_{2}

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Solution

The correct option is D $K O_{2}$
$K O_{2}$ has $O_{2}^{-}$ ion.

$O_{2}^{-}$ has one unpaired electron.

The electronic configuration of the $O_{2}^{-}$ ion containing 17 electrons can be written as: $1 s^{2} * 1 s^{2} 2 s^{2} * 2 s^{2} 2 p z^{2} 2 p x^{2} 2 p y^{2} * 2 p x^{2} * 2 p y^{1}$ .

Hence, option D is correct.

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L i_{2} O, C a O, N a_{2} O_{2}, K O_{2}, M g O and K_{2} O

[N i (C O)_{4},, [N i C l_{4}]^{2 -}, [C o (N H_{2}), C l_{2}] C l, N a_{3} [C o F_{6}], N a_{2} O_{2} and C s O_{2} .]

K O_{2}, N O_{2}, S O_{2}, B a O_{2}, C l O_{2}, O_{2}, N O, N_{2} O, O_{3}, C O

[N i (C O)_{4}]

[N i C l_{4}]^{2 -}

[C o (N H_{3})_{4} C l_{2}] C l

N a_{3} [C o F_{6}]

N a_{2} O_{2}

C s O_{2}

[N i (C O)_{4}],

N i C l_{4}]^{2 -}

[C o (N H_{3})_{4} C l_{2}] C l

N a_{3} [C o F_{6}],

N a_{2} O_{2}

C s O_{2}

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