Among the following, third ionization enthalpy is highest for
A
Mg
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B
B
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C
Be
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D
Al
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Solution
The correct option is C Be Let's first look at the electronic configurations.
(Magnesium) Mg - 1s22s22p63s2
(Boron) B - 1s22s22p1
(Beryllium) Be - 1s22s2
(Aluminium) Al - 1s22s22p63s23p1
So, it is easy to deduce that both Be and Mg would have a significant increase in ionization enthalpy after losing 2 electrons as they are losing an entire shell.
But the 3rd ionization enthalpy of Be would be much higher since the shielding from the inner electrons is much lesser as compared to that of Mg.