Question

Among the following transition elements, pick out the element/elements with highest second ionization energy:

$\left(i\right)V$(At.no $=23$) $\left(ii\right)Cr$ (At. no.$=24$)
$\left(iii\right)Mn$ (At. no.$=25$) $\left(iv\right)Cu$ (At. no.$=29$)
$\left(v\right)Zn$ (At. no. $=30$)

• A. $\left(i\right)$ and $\left(iii\right)$
• B. $\left(ii\right)$ and $\left(v\right)$
• C. only $\left(iii\right)$
• D. only $\left(iv\right)$

Answer 1

The correct option is D only $\left(iv\right)$

${}_{29}Cu$ has the electronic structure of $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}3d^{10}$. Hence second ionization will result in removal of electron from a completely filled d orbital. Hence it has highest second ionization energy.