No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D (a) f(x)=ax+a−x2 and f (– x) = f(x) (b) f(x)=xex−1+x2 and f(x) – f (–x) = 0 (c) f(x)=√1+x+x2+√1−x+x2 ⇒ f(–x) = f(x) ⇒ ‘f’ is even (d) f(x)=x3+sinx f(–x) = –f(x) ⇒ ‘f’ is odd.