The correct option is B F2
As we move down in group-17, electronegativity decreases. Fluorine is the most electronegative element. so forming F− is the most energetically favourable of the standard reductions. This makes fluorine the most powerful oxidising agent. The order of strong oxidizing agent of halogens will be:
F2>Cl2>Br2>I2
Therefore, the correct answer is B.