You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrochemical Series

Among the fol...

Question

Among the following which is the strongest oxidising agent?

B r_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $F_{2}$
The Halogen which has higher value of standard reduction potential will be the strongest oxidizing agent.
Oxidizing agent oxidize other elements and reduce itself. Standard reduction potential value of these four halogen molecule is in the following order,
$F_{2} > C l_{2} > B r_{2} > I_{2}$
The strongest oxidizing agent is $F_{2}$ .

Suggest Corrections

Similar questions

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

Join BYJU'S Learning Program