Question

Among the following, which one is a wrong statement?

• A. $Se{F}_4$ and $C{H}_4$ have same shape.
• B. ${I_3}^{-}$ has linear shape.
• C. $P{H}_5$ and $BiC{l}_5$ do not exist.
• D. $p\pi -d\pi$ bonds are present in $S{O}_2$.

Answer 1

The correct option is A $Se{F}_4$ and $C{H}_4$ have same shape.

(1) $Se{F}_4$ shape is see-saw whereas $C{H}_4$ is tetrahedral.

(2) ${I_3}^{-}-s{p}^{3}d$, $lp=3;bp=2$, shape is linear.

(3) The extent of overlapping of d orbital of phosphorous and 1s orbital of hydrogen is very less because the energy difference between them is too high for favourable bond formation so that the most of 1s orbital of hydrogens interact with p orbitals so that we can form $P{H}_3$.

$P{H}_5$ doesn't exists as d-s orbital overlapping is less, it will dissociate into $P{H}_3$ and $H_2$.

In case of $BiC{l}_5$, it is due to the inert pair +5 state is not stable.

(4) $S{O}_2$ : $O=S=O$

So, both $p\pi -p\pi$ and $p\pi -d\pi$ bonds are present.

Hence, option A is correct.