Question

Among the following, which one is a wrong statement ?

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> NEET 2016

Answer 1

Correct option is $\left(A\right)$
$\left(1\right)Se{F}_4\text{shape is see-saw whereas}C{H}_4\text{shape is tetrahedral.}$


$\left(2\right)I_3^{-}s{p}^{3}d,1p=3;by=2,\text{shape is linear.}$

$\left(3\right)$ The extent of overlapping of $d$ orbital of phosphorous and is orbital of hydrogen is very less because the energy difference between them is too high for favourable bond formation so that the most of $1s$ orbital of hydrogen
interacts with $p$ orbitals to form $P{H}_3$.

$P{H}_5$ doesn't exists as $d-s$ orbital overlapping is less. it will dissociate into $P{H}_{3}and{H}_2$.

In case of $BiC{l}_5$, it is due to the inert pair $+5$ state is not stable.

$\left(4\right)S{O}_2:O=S=O$

So, both $p\pi -p\pi andp\pi -d\pi$ bonds are present.

Hence, option $A$ is correct.