Among the given compounds, the compound which is most susceptible to a nucleophilic attack at the carbonyl group is :

C H_{3} C O C l

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C H_{3} C H O

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C H_{3} C O O C H_{3}

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C H_{3} C O O C O C H_{3}

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Solution

The correct option is B $C H_{3} C O C l$
We know the following facts:
1. Weaker bases are better leaving groups.
2. Strong acids have very weak conjugate bases.
Here, $H C l$ is a very strong acid.
So, the chloride ion is a very weak base as compared to others.
Hence, it is the best leaving group in nucleophilic acyl substitution.
Besides, the $C l$ group also activates the carbonyl group towards nucleophilic substitution reaction due to its $- I$ effect.
Therefore, $C H_{3} C O C l$ is most susceptible to nucleophilic attack at the carbonyl group because it will show fastest rate of reaction.

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