Among the halogens, the one which is oxidised by nitric acid is:

fluorine

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iodine

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chlorine

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bromine

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Solution

The correct option is B iodine
Reducing properties increase from $F$ to $I$ so it is oxidised by nitric acid.

$I_{2} + 10 H N O_{3} \to 2 H I O_{3} + 10 N O_{2} + 4 H_{2} O$

Nitric acid oxidizes iodine to iodic acid, $H I O_{3}$ and not periodic acid, $H I O_{4}$ , which is of a higher oxidation state.

Hence, option B is the correct answer.

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