Among the metal carbonyls $[M n (C O)_{6}]^{+}, [T i (C O)_{6}], [C r (C O)_{6}]$ and $[V (C O)_{6}]^{-}$ the $C - O$ bond order would be lowest in :

[M n (C O)_{6}]^{+}

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[T i (C O)_{6}]^{2 -}

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[C r (C O)_{6}]

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[V (C O)_{6}]^{-}

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Solution

The correct option is A $[M n (C O)_{6}]^{+}$
The $C - O$ bond order would be lowest at $[M n (C O)_{6}]^{+}$ .

The metal bears a positive charge which makes the back donation process favourable.

The electrons from the metal fill the $π -$ antibonding orbital of CO, they weaken the carbon-oxygen bond.

Hence, the correct option is A.

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