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Question

Among the statements (I–IV), the correct ones are:

(I) Be has a smaller atomic radius compared to Mg.

(II) Be has higher ionization enthalpy than Al.

(III) Charge/radius ratio of Be is greater than that of Al.

(IV) Both Be and Al form mainly covalent compounds.


A

(I), (II) and (IV)

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B

(I), (II) and (III)

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C

(II), (III) and (IV)

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D

(I), (III) and (IV)

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Solution

The correct option is A

(I), (II) and (IV)


Explanation for correct option:

(A) (I), (II) and (IV)

Statement (I):

  1. Be has a smaller atomic radius compared to Mg.
  2. This is so because down the group size of elements increases and in periodic table Be and Mg are elements of same group but Be is placed above Mg, so it is smaller in size.

Statement (II):

  1. Be has higher ionization enthalpy than Al.
  2. This is so because Be has full filled s-subshell electronic configuration 1s2,2s2so it require more energy to remove electron from full filled subshell.

Statement (IV):

  1. Both Be and Al form mainly covalent compounds.
  2. This is so because these elements have high second ionization enthalpies.
  3. So they form covalent bonds by sharing electrons rather than forming ionic bonds by donating electrons.

Explanation for incorrect options:

(B) (I), (II) and (III)

  1. From the above discussion it can be observed that statement (I) and (II) are correct.
  2. Statement (III): Charge/radius ratio of Be is greater than that of Al.
  3. This is so because Be and Al have similar charge/radius ratio as they exhibit diagonal relationship.
  4. Hence, the statement is incorrect.

(C) (II), (III) and (IV)

From the above discussion, it can be observed that statement (II) and (IV) are correct but statement (III) is incorrect.

(D) (I), (III) and (IV)

From the above discussion, it can be observed that statement (I) and (IV) are correct but statement (III) is incorrect.

Hence option C is correct, statements (I), (II) and (IV) are correct.


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