Question

Among three numbers, the average of the first and the second is greater than the average of the second and the third by 16.
What is the difference between the first and the third of the three numbers?

• A. 32
• B. 28
• C. 26
• D. 30
• E. 33

Answer 1

The correct option is A

32

Let the numbers be x, y and z.

Then,$\left(\frac{x+y}{2}\right)-\left(\frac{y+z}{2}\right)=16$

$(x+y)-(y+z)=32x-z=32$