Question

Amongst the element with the following electronic configurations, which one of them may have the highest ionization energy?

• A. $\left[Ne\right]3s^{2}3p^1$
• B. $\left[Ne\right]3s^{2}3p^3$
• C. $\left[Ne\right]3s^{2}3p^2$
• D. $\left[Ar\right]3d^{10}4s^{2}4p^3$

Answer 1

The correct option is B $\left[Ne\right]3s^{2}3p^3$

The elements having half-filled and fully filled orbitals in electronic configuration has more ionisation energy than the value observed in trends.

Here, in [Ne] $3s^{2}3p^3$, 'p' orbital is half-filled.

Outermost electronic configuration $3s^{2}3p^3$.

So it has highest ionisation energy among options.