The correct option is C CH3COOH
Acetic acid, CH3COOH would not respond to iodoform test. In the mechanism of haloform reaction, in the first step, base deprotonates most acidic alpha H atom (of methyl keto group).
In acetic acid, the most acidic proton is attached to O atom. So deprotonation of α−hydrogen does not occur and hence no haloform reaction.