Question

Amongst the following elements (whose electronic configuration are given below) the one having the highest ionization energy is-

• A. $\left[Ne\right]3s^{2}3p^1$
• B. $\left[Ne\right]3s^{2}3p^3$
• C. $\left[Ne\right]3s^{2}3p^2$
• D. $\left[Ne\right]3d^{10}4s^{2}4p^3$

Answer 1

The correct option is B $\left[Ne\right]3s^{2}3p^3$

(b) ionization energy increases with increasing atomic number in a period while it decreases on moving down the group.
IE of element with electronic configuration (d) is the lowest because of it's biggest size among all.Among the remaining three elements of the same period (3rd), IE of the element with configuration (b) is the highest due to greater stability of exactly half filled 3p subshell.