Question

Amongst the following hydroxides, the one which has the lowest value of $K_{sp}$ at ordinary temperature is

• A. $Mg(OH{)}_2$
• B. $Ca(OH{)}_2$
• C. $Ba(OH{)}_2$
• D. $Be(OH{)}_2$

Answer 1

The correct option is D $Be(OH{)}_2$

Electronegativity order is as follows : Be>Mg>Ca>Ba. Hence order of tendency of loosing $O{H}^{-}$ is $Ba(OH{)}_2>Ca(OH{)}_2>Mg(OH{)}_2>Be(OH{)}_2$ $Be(OH{)}_2$ has least $K_{sp}$.