Amongst the following, $S F_{6}$ , ${B F_{6}}^{3 -}$ , $S F_{4}$ , ${A l F_{6}}^{3 -}$ , $P H_{5}$ , $N C l_{5}$ , $S C l_{6}$ , the total number of species which does/do not exist is:

5

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4

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6

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3

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Solution

The correct option is B $4$
(A) Amongst hexahalides of sulfur, only $S F_{6}$ is exceptionally stable for a steric reason. In $S C l_{6}$ , smaller $S$ cannot accommodate six larger $C l^{-}$ ions.
(B) $P H_{5}$ does not exist as there is a large difference in the energies of $s, p$ and $d$ orbitals of $P$ and hence it does not undergo $s p^{3} d$ hybridisation.
(C) $N C l_{5}$ does not exist as there is no d-orbital with $N .$
(D) ${B F_{6}}^{3 -}$ does not exist due to the absence of vacant d-orbital in $B$ and hence it cannot exceed its covalency beyond four.

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