Amongst the following, the most stable complex is:

[F e (H_{2} O)_{6}]^{3 +}

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[F e (N H_{3})_{6}]^{3 +}

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[F e (C_{2} O_{4})_{3}]^{3 -}

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[F e C l_{6}]^{3 -}

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Solution

The correct option is B $[F e (C_{2} O_{4})_{3}]^{3 -}$
In each of the given complex, Fe is in $+ 3$ oxidation state. As $C_{2} O_{4}^{2 -}$ is a bidentate chelating ligand, it forms rings and hence $[F e (C_{2} O_{4})_{3}]^{3 -}$ is the most stable complex.

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Similar questions

[F e (H_{2} O)_{6}]^{3 +}

[F e (N H_{3})_{6}]^{3 +}

[F e (C_{2} O_{4})_{3}]^{3 -}

[F e C l_{6}]^{3 -}

Amongst the following, the most stable complex is

(i) [Fe(H₂O)₆]³⁺

(ii) [Fe(NH₃)₆]³⁺

(iii) [Fe(C₂O₄)₃]^3-

(iv) [FeCl₆]^3-

{[F e (H_{2} O)_{6})]}^{3 +}

{[F e {(C N)}_{6}]}_{6}^{3 -}

{[F e {(C_{2} O_{4})}_{3}]}_{3}^{3 -}

{[F e {(C l)}_{6}]}_{6}^{3 -}

[F e (H_{2} O)_{6}]^{3 +}, [F e (C N)_{6}]^{3 -}, [F e (C_{2} O_{4})_{3}]^{3 -}

[F e C l_{6}]^{3 -}

[F e (H_{2} O)_{6}]^{3 +}, [F e (C N)_{6}]^{3 -}, [F e (C_{2} O_{4})_{3}]^{3 -}

[F e C l_{6}]^{3 -}

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