Amongst the following, the total number of compounds whose aqueous solution turns red litmus paper blue is:
$K C N, K_{2} {S O}_{4}, {({N H}_{4})}_{2} {C_{2} O}_{4}, N a C l, Z n {({N O}_{3})}_{2}, F e {C l}_{3}, K_{2} C O_{3}, {N H}_{4} {N O}_{3}, L i C N$

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Total $3$ compounds.
Salts of weak acids and strong base will give basic solution on hydrolysis and will turn red litmus to blue $K C N, K_{2} C O_{3}$ and $L i C N$ are such type of salts.

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Q. Among the following, the total number of compounds whose aqueous solution turns red litmus to blue is:

K C N, K_{2} {S O}_{4}, {({N H}_{4})}_{2} C_{2} O_{4}, N a C l, Z n {({N O}_{3})}_{2}, F e {C l}_{3}, K_{2} {C O}_{3}, {N H}_{4} {N O}_{3}, L i C N

Q. Amongst the following, the total no. of compound whose aq. Solution turn red litmus paper blue is______.

K C N, K_{2} {S O}_{4}, ({N H}_{4})_{2} C_{2} O_{4}, N a C l, Z n ({N O}_{3})_{2}, F e {C l}_{3}, K_{2} {C O}_{3}, {N H}_{4} {N O}_{3}, L i C N

Q. Aqueous solution of which of the following salts turns the red litmus blue?

When a red litmus paper is dipped in the aqueous solution of $X$ there is no change in colour.
When a blue litmus paper is dipped in the same solution it turns red.
Which among the following options can be the chemical $X$ ?

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Amongst the following, the total number of compounds whose aqueous solution turns red litmus paper blue is:KCN,K2SO4,(NH4)2C2O4,NaCl,Zn(NO3)2,FeCl3,K2CO3,NH4NO3,LiCN

Total 3 compounds.Salts of weak acids and strong base will give basic solution on hydrolysis and will turn red litmus to blue KCN,K2CO3 and LiCN are such type of salts.

Amongst the following, the total number of compounds whose aqueous solution turns red litmus paper blue is:
$K C N, K_{2} {S O}_{4}, {({N H}_{4})}_{2} {C_{2} O}_{4}, N a C l, Z n {({N O}_{3})}_{2}, F e {C l}_{3}, K_{2} C O_{3}, {N H}_{4} {N O}_{3}, L i C N$

Total $3$ compounds.
Salts of weak acids and strong base will give basic solution on hydrolysis and will turn red litmus to blue $K C N, K_{2} C O_{3}$ and $L i C N$ are such type of salts.