Amongst the reactant pairs given below, how many of them yield no product?

$(a) M g (s) + C u S O_{4} (a q)$

$(b) C u (s) + Z n S O_{4} (a q)$

$(c) Z n (s) + H C l (a q)$
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Solution

The correct option is A 1
Out of the three given reactions, (a) and (c) will yield products as shown below.

$(a) M g (s) + C u S O_{4} (a q) \to M g S O_{4} (a q) + C u (s)$

$(c) Z n (s) + 2 H C l (a q) \to Z n C l_{2} (a q) + H_{2} (g)$

This is because Mg is highly reactive than Cu and hence can be displaced easily by Mg. Similarly, Zn is more reactive than H and thus gets displaced.

However, (b) will not yield any product as Cu is a less reactive metal when compared to Zn. Thus, there will be no such reaction.

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Similar questions

(a) M g (s) + C u S O_{4} (a q)

(b) C u (s) + Z n S O_{4} (a q)

(c) Z n (s) + H C l (a q)

P b, A u, M g, S n, F e, A l, A g, H g, N a, Z n, C u, C a

C u

Z n

Ti = 22, Cr = 24, Cu = 29, Zn = 30

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