1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XI
Chemistry
Law of Radioactivity
Amount of 53I...
Question
Amount of
53
I
128
(
t
1
2
=
25
m
i
n
)
l
e
f
t
after 75 minutes is
A
1
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
1
8
N
N
0
=
(
1
2
)
T
t
1
2
N
N
0
=
(
1
2
)
75
25
;
N
N
0
=
(
1
2
)
3
=
1
8
Suggest Corrections
4
Similar questions
Q.
Amount of
53
I
128
(
t
1
2
=
25
m
i
n
)
l
e
f
t
after 75 minutes is
Q.
Amount of
53
I
128
(
t
1
2
=
25
m
i
n
)
l
e
f
t
after 75 minutes is
Q.
What is the time :
2
hours
25
minutes after
9
:
40
a.m.
Q.
75
×
75
+
2
×
75
×
25
+
25
×
25
i
s
e
q
u
a
l
t
o
Q.
What is the half - life of a radioactive substance if
75
%
of any given amount of the substance disintegrates in
60
minutes?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
CHEMISTRY
Watch in App
Explore more
Law of Radioactivity
Standard XI Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app