Question

Amount of heat required to convert 10 g of ice at $0^{\circ }$ Cof water at ${20}^{\circ }$C is

• A. 80 cal
• B. 100 cal
• C. 1000 cal
• D. 540 cal

Answer 1

The correct option is C 1000 cal

Heat required to convert 10 g of ice at $0^{\circ }$C to water at $0^{\circ }$C
$Q_1$= mL = 10 $\times$ 80 cal = 800 cal
Heat required to raise the temperature of water from $0^{\circ }$C to ${20}^{\circ }$C
$Q_2$ = mc$\theta$ = 1 $\times$ 10 $\times$ 20 = 200cal
Total heat required
= $Q_1$ + $Q_2$ = 800 + 200 = 1000 cal