Amount of oxygen required for combustion of $1$ kg of a mixture of butane and isobutane is:

1.8

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2.7

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4.5

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3.58

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Solution

The correct option is D $3.58$ kg
Butane and isobutane has the same molecular formula $C_{4} H_{1} 0$
$C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O$
58g of $C_{4} H_{10}$ requires $O_{2}$ = $\frac{13}{2} \times 32$
1000g of $C_{4} H_{10}$ requires $O_{2}$ = $\frac{13 \times 32 \times 1000}{2 \times 58}$
= 3.586 Kg

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