Question

Amount of oxygen required for combustion of 1 kg of a mixture of butane is:

• A. 1.8 kg
• B. 2.7 kg
• C. 4.5 kg
• D. 3.58 kg

Answer 1

The correct option is D 3.58 kg

$C_4{H}_{10}+\frac{13}{2}{O}_2\to 4C{O}_2+5H_{2}O$
58g $C_4{H}_{10}$ requires $\frac{13\times 32}{2}$ g $O_2$.
$\therefore$ 1000g $C_4{H}_{10}$ requires $\frac{13\times 32\times 1000}{258}=358.62g=3.58kg{O}_2$.