Amplitude of a travelling wave on a string is 1mm. If linear mass density of string is 10−4kgm−1 , tension in the string is 1N and frequency of vibration is 10Hz, then average power needed to maintain such waves in string is : (π2=10)
A
3×10−5W
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B
2×10−5W
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C
4×10−5W
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D
10−5W
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Solution
The correct option is A2×10−5W Pav=μω2A2V2=10−4×4π2×102×10−6×√1042 =2π2×10−6 =2×10−5W