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Standard XII
Physics
Power in an AC Circuit
Amplitude of ...
Question
Amplitude of electric field in a laser beam of power 4.4 mW with cross-sectional area of
2
m
m
2
is
A
√
2
3
k
V
/
m
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B
√
5
3
k
V
/
m
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C
2
k
V
/
m
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D
23
2
k
V
/
m
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Solution
The correct option is
B
√
5
3
k
V
/
m
Intensity
I
=
P
o
w
e
r
A
r
e
a
=
4.4
×
10
−
3
2
×
10
−
6
=
4.4
2
×
10
3
W
/
m
2
I
=
1
2
ε
0
C
E
2
0
⇒
4.4
2
×
10
3
=
1
2
×
8.8
×
10
−
12
×
3
×
10
8
E
2
0
E
2
0
=
4.4
×
10
7
8.8
×
3
=
10
6
×
10
6
⇒
E
0
=
√
5
3
×
10
3
V
/
m
Suggest Corrections
0
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Q.
Amplitude of electric field in a laser beam of power 4.4 mW with cross-sectional area of
2
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Q.
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[
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Q.
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Q.
A laser beam has intensity
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