Question

An $8\mu F$ capacitor is connected across a $220V,50Hz$ line. What is the peak value of charge through the capacitor?

• A. $2.5\times {10}^{-3}C$
• B. $2.5\times {10}^{-4}C$
• C. $5\times {10}^{-5}C$
• D. $7.5\times {10}^{-2}C$

Answer 1

The correct option is A $2.5\times {10}^{-3}C$

Peak value of charge through capacitor = $Q=C{V}_{max}=8\times {10}^{-6}\times 220\sqrt{2}=2.5\times {10}^{-3}C$