An 8N force acts on a rectangular conductor 20cm long placed perpendicular to a magnetic field. Determine the magnetic field induction if the current in the conductor is 40 A.

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Solution

Given force, $F = 8 N$
Length of conductor $l = 20 c m = 0.2 m$
Current in conductor, $I = 40 A$
Now, magnetic field B=?
Using $F = B I l$
$⟹ B = \frac{F}{I l} = \frac{8}{0.2 \times 40} = 1 T$
$⟹ \to B = 1 Tesla$

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An 8N force acts on a rectangular conductor 20cm long placed perpendicular to a magnetic field. Determine the magnetic field induction if the current in the conductor is 40 A.

Given force, F=8NLength of conductor l=20cm=0.2mCurrent in conductor, I=40ANow, magnetic field B=?Using F=BIl⟹B=FIl=80.2×40=1T⟹→B=1 Tesla

Given force, $F = 8 N$
Length of conductor $l = 20 c m = 0.2 m$
Current in conductor, $I = 40 A$
Now, magnetic field B=?
Using $F = B I l$
$⟹ B = \frac{F}{I l} = \frac{8}{0.2 \times 40} = 1 T$
$⟹ \to B = 1 Tesla$