Question

An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.

Answer 1

Given,
n = 60
a = 7
l = 125
$\therefore$ a + (n-1)d = 125
7 + (59)d = 125
d = 2
$\therefore a_{32}=a+(32-1)d$
= 7 + (31)2
= 69
32nd term is 69.