Given:
R=220 Ω, L=0.7 H, Vrms=220 V
ω=50 Hz
The impedance of the circuit is,
Z=√R2+ ω2L2=√R2+(2πfL)2
=√(220)2+(2×3.14×50×0.7)2
⇒Z=311 Ω
Now, cosϕ=RZ=220311=0.707
Also, irms=VrmsZ=220311=0.707 A
∴ The power absorbed in the circuit
P=Vrmsirmscosϕ
=(220)(0.707)(0.707)
=110.08 W