Question

An AC circuit containing $80mH$ inductor and a $60\mu F$ capacitor is in series with $15\Omega$ resistance. They are connected to $230V,50Hz$ AC supply. What is the total average power absorbed by the circuit?

• A. zero
• B. $5$ watt
• C. $40$watt
• D. $10$ watt

Answer 1

The correct option is A zero

No correct option.

Given, $Inductance,L=80mH=80\times {10}^{-3}H,Capacitance,C=60\mu f=60\times {10}^{-6}F$

Supply voltage, $v=230,Frequency=50Hz$,

Angular velocity $\omega =2\pi v=100\pi rad/s$

Peak voltage $v\sqrt{2}=230\sqrt{2}v$

Since the average power consumed by the inductor, is zero, as the actual voltage leads the current by $\frac{\pi }{2}$

And the average voltage consumed by the capacitor is zero, as voltage lags current by $\frac{\pi }{2}$

Thus the total power supplied (average over one cycle)is zero.